Answer :

We know that the area A of a sector of angle \( \theta \) in a circle of radius r is given by \( A \ = \ \frac{ \theta}{360} \ × \ \pi r^2 \).

Here \( r \ = \ 6 \ cm \), \( \theta \ = \ 60° \)

\(\therefore \) \( A \ = \ \frac{60}{360} \ × \ \frac{22}{7} \ × \ 36 \ \)

\( = \ ( \frac{132}{7} ) \ cm^2 \)

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